(t) = −2(t − 15)2 + 506, where height, a(t), is in meters, and time, t, is in seconds. the path of missile b is shown below.

Let's solve step by step:
t=(-2(t-15))(2)+506
Step 1:Simplify both sides of the equation
t=(-2(t-15))(2)+506

Simplify (show steps)
t=-4t+566
Step 2:Add 4t to both sides
t=4t=-4t+566+4t
5t=566
Step 3:Divide both sides by 5
5t/5=566/5

t=566/5

Hope this helps!

Teri ma ki chhut‌‌‌‌‌‌