John rolls a six-sided number cube twice. what is the probability of getting an even number and then an odd number?
5/6
1/4
1/2
1/6

Option 2 -

Step-by-step explanation:

Given : John rolls a six-sided number cube twice.

To find : What is the probability of getting an even number and then an odd number?    

Solution :              

When rolls a six-sided number cube twice

(1,1)  (1,2) (1,3)  (1,4)  (1,5)  (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

Now,  

Favorable outcome of getting an even number and then an odd number:

(2,1) (2,3) (2,5) (4,1) (4,3) (4,5) (6,1) (6,3) (6,5)

So, Favorable outcome = 9

Total number of outcome = 36

Therefore, Option 2 is correct.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°