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Mathematics, 09.12.2019 12:31 TradeOK158
Mrs. culland is finding the center of a circle whose equation is x2 + y2 + 6x + 4y – 3 = 0 by completing the square. her work is shown.
x2 + y2 + 6x + 4y – 3 = 0
x2 + 6x + y2 + 4y – 3 = 0
(x2 + 6x) + (y2 + 4y) = 3
(x2 + 6x + 9) + (y2 + 4y + 4) = 3 + 9 + 4
which completes the work correctly?
(x – 3)2 + (y – 2)2 = 42, so the center is (3, 2).
(x + 3)2 + (y + 2)2 = 42, so the center is (3, 2).
(x – 3)2 + (y – 2)2 = 42, so the center is (–3, –2).
(x + 3)2 + (y + 2)2 = 42, so the center is (–3, –2).
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Mrs. culland is finding the center of a circle whose equation is x2 + y2 + 6x + 4y – 3 = 0 by comple...
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