The interior angles formed by the sides of a pentagon have measures that sum to 540°. what is the measure of angle b?

m∠b=

m∠B = 110°

Step-by-step explanation:

We know that,

The sum of the measures of the angles in a pentagon is 540°.

So, we get,

130 + (x-5) + (x+30) + 75 + (x-35) = 540

i.e. 3x + (130+30+75) - (5+35) = 540

i.e. 3x + 235 - 40 = 540

i.e. 3x + 195 = 540

i.e. 3x = 540 - 195

i.e. 3x = 345

i.e. x= 115°

Now, as m∠B = (x-5)° = (115-5)° = 110°

Hence, the measure of angle B is 110°.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2