Any number that is divisible by 3 is divisible by nine

I think what you are trying to ask is what number is divisible by three and nine
   multiply 3 and 9 to get your answer
        = 27
  27 because it can be divided by 3 and = 9 and can be divided by 9 and = 3

All numbers written only with the digit 9 are divisible by 9 For example: 9, 99, 999, 99999 Lets us take any number , for example 324 324 can be written as a sum of hundreds, tens and ones like this: 324 = 300 + 20 + 4 or 324 = 100 + 100 + 100 + 10 + 10 + 4 But 100 = 99 + 1 and 10 = 9 + 1 Then 324 = 99 + 99 + 99 + 3 + 9 + 9 + 2 + 4 = (99 + 99 + 99 + 9 + 9)+ (3 + 2 + 4) The sum in the first brackets is divisible by 9 because all the addends are divisible by 9. If the sum in the second brackets (3+2+4) is also divisible by 9 than the whole number 324 is divisible by 9. Because the sum 3 + 2 + 4 is divisible by 9, 324 is also divisible by 9

Ya i could just need to know what type of math