Aregular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. what is the approximate area of the heptagon rounded to the nearest whole number? recall that a heptagon is a polygon with 7 sides.

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Step-by-step explanation:

We have been given that a regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm.      

We will use area of a heptagon formula to find the area of our given heptagon.    

, where, a represents each side of heptagon.

Upon substituting a=24.18 cm we will get,

Therefore, area of our given heptagon will be approximately .

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option