Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the braking force acting on the truck is 11,000 n

Since the truck was in motion before the brakes were applied, it will decelerate within the 4s before coming to a stop. Hence the acceleration is .

When the truck comes to a stop, It will have a final velocity of .

Also the initial velocity is 22.0 m/s. This means, and time,  .

We can use the relation,

to determine the acceleration of the truck.

Let us now plug in all the values to obtain,

Using the relation,

the magnitude of the braking force is

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i