Given that ∠xqr = 180° and ∠lqm = 180°, which equation could be used to solve problems involving the relationships between ∠xqm and ∠rqm?

(136 − 2a) + (3a + 39) = 180

Step-by-step explanation: Supplementary angles add to 180°

he can buy 4lbs. of live bait and 1lbs of natural bait

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)