Anew car is purchased for 16400 dollars. the value of the car depreciates at 8.25% per year. what will the value of the car be, to the nearest cent, after 10 years?

$6932.73.

Step-by-step explanation:

Principal = $16400

Rate of decrease = 8.25%

Now we are supposed to find What will the value of the car be, to the nearest cent, after 10 years?

Formula :

where A is the amount

r is the rate of decreasing in % =8.25%

t is the time =10

P is the principal =$16400

Substituting the values:

Hence the value of the car after 10 years will be $6932.73.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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hi! i think the answer is 1/2 : )