There are 18 students participating in a spelling bee. how many ways can the students who go first, second, third, and fourth be chosen?

a.
73,440 ways
c.
4,896 ways
b.
1,028,160 ways
d.
13,366,080 ways

a. 73,440 ways

Step-by-step explanation:

To find the number of ways to choose first, second, third and fourth in a spelling bees given that 18 student participate in the spelling bee, we will simply use permutation.

Thus, the standard formula is; n  =  n !   /  (n-r)!

From the question above, our n is equal to eighteen and  our r is equal to four That is; n= 18 and r = 4

Inserting these value into the formula

n  =  n !   /  (n-r)!

18    =    18 !  /   (18 - 4) !

             = 18 !   /   14 !

             = 18 × 17 × 16 × 15 × 14!      /     14!

The 14! on the numerator will cancel-out the 14! on the denominator, hence;

18  =  18 × 17×16×15

           =73,440

Therefore  we can choose the students who goes first, second, third and fourth position in 73, 440 ways.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)