Find the x- and y-intercepts of the function f(x) = log(2x + 1) − 1.

Alright, here's your answer.

y-intercept is computed (not found) by assigning x = 0 and computing y: here that is f(0) = Log(2*0 + 1) – 1 = Log(1) – 1 = 0 – 1 = -1 
y-intercept is (0, -1) 

x-intercept is computed by solving f(x) = 0 for x: here that is 
0 = Log(2x + 1) – 1 → 1 = Log(2x + 1) 

Assuming the Log cited is base 10, then 10^1 = 10^Log(2x + 1) = 2x + 1 

That’s 10 = 2x + 1 

Therefore 9 = 2x 
x = 9/2 = 4.5 
Check this result in the original equation, I did! 

Your answer is - x-intercept is (4.5, 0)

I hope I helped! :)