Use the rational zeros theorem to write a list of all possible rational zeros of the function. (2 points) f(x) = 3x3 + 39x2 + 39x + 27

In this equation, p=27 because it is the last term and q=3 because it is the coefficient of the first term. First find all divisors of these numbers:
27: 1, 3, 9, 27
3:1, 3
Then use +/- p/q to find all possible combinations 
+/-1, +/-3, +/-9, +/-27, +/- 1/3

Or your answer can be written as: 1, -1, 3, -3, 9, -9, 27,-27, 1/3, -1/3

Hope this helps!