Abag contains 10 blue, 6 green, and 4 red marbles. you choose one marble. without putting it back, you choose a second marble. what is the probability that you first choose a green marble and then a blue marble?

Step-by-step explanation:

Given :

A bag contains 10 blue, 6 green, and 4 red marbles.

You choose one marble. Without putting it back, you choose a second marble.

To Find: What is the probability that you first choose a green marble and then a blue marble?

Solution:

No. of blue balls = 10

No. of green balls =6

No. of red marbles =4

Total no. of marbles = 10+6+4 =20

Since we are given that first he choose a green marble

So, probability of getting green marble :

=

Since he choose second marble without replacement

So, after choosing first ball . The total no. of balls will be 19

So, Probability of getting blue marble in second draw :

=

The probability that you first choose a green marble and then a blue marble:

Hence the probability that you first choose a green marble and then a blue marble is  

could

step-by-step explanation:

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step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )