Which set of ordered pairs could be generated by an exponential function?
(0, 0), (1, 1), (2, 8), (3, 27)
(0, 1), (1, 2), (2, 5), (3, 10)
(0, 0), (1, 3), (2, 6), (3, 9)
(0, 1), (1, 3), (2, 9), (3, 27)

(0, 1), (1, 3), (2, 9), (3, 27)

Step-by-step explanation:

We need to find which ordered pair represents exponential function

(0, 0), (1, 1), (2, 8), (3, 27)

When x=2 , y = 2^3= 8

x=3, y= 3^3 = 27

x=0, y cannot be 0 in an exponential function because anything^0 is 1

(0, 1), (1, 2), (2, 5), (3, 10)

It does not represents exponential function because y values does not increasing exponentially

(0, 0), (1, 3), (2, 6), (3, 9)

It does not represents exponential function because y values are increasing by 3

(0, 1), (1, 3), (2, 9), (3, 27)

When x= 0 , y = 3^0=1

x= 1 , y = 3^1=3

x= 2 , y = 3^2=9

x= 3 , y = 3^3=27

The values of y are increasing exponentially. So it represents exponential function

d

step-by-step explanation:

d

the correct answer is $7.38

step-by-step explanation: