Write an equation in general form of the line passing through (3, -5) whose slope is the negative reciprocal of -1/4

Negative reciprocal means
-1/4 times x=-1 solve for x
multiply both sides by -4/1
x=-4
so slope=-4
y=mx+b
m=slope, b=y intercpet
y=-4x+b
input 3 for x and -5 for y
-5=-4(3)+b
-5=-12+b
add 12 to both sides
7=b
the equation in slope intercept form is y=-4x+7
that is my standard form
another standard form is
y+4x=7

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