Which equation can be used to find the perimeter of a regular pentagon with side of length 6 m

a. p=5+6
b. p=6/5
c. p=5(6)
d. p=2(5)+2(6)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

4444444444444 i think

x = 3 ± √(5+y)

beluga wheeeaaalle matt

step-by-step explanation: