The radius of a cylindrical gift box is (3x +4)) inches. the height of the gift box is twice the radius. what is the surface area of the cylinder? write your answer as a polynomial in standard form.

The answer is 54πx² + 144πx + 96π

The surface area of cylinder (SA) is:
SA = 2 π r h + 2 π r²

The height of the gift box is twice the radius: h = 2r

r = 3x + 4
h = 2(3x + 4) = 6x + 8

SA = 2 π r h + 2 π r²
SA = 2π (r * h + r²)
SA = 2π ((3x + 4)(6x + 8) + (3x + 4)²)
SA = 2π(18x² + 24x + 24x + 32 + 9x² + 24x + 16)
SA = 2π(27x² + 72x + 48)
SA = 54πx² + 144πx + 96π

You need to divide 210 square inches by 35 inches and that’s going to give you 6 inches and that’s the length of the hypothenuse of the right triangle i hope that this you : )

Which of the following values are in the range is the function graphed below? check all that applya.3b.1c.0d.-2e.5f.2a