Aright triangle has one leg that is 13 cm long. the hypotenuse is 27 cm long l. find the area of the triangle to the nearest tenth .

For a right angle triangle,

Hypotenuse² = base² + height² 
Hypotenuse = 27 cm
One leg (x) = 13 cm(could be either base or height)
Let other leg be y

Hypotenuse² = x² + y²

27² = 13² + y²
y² = 27² - 13² = 729 - 169 = 560 = 23.66cm

Area of triangle = 1/2 bh = 1/2 x 13 x 23.66 = 153.79 cm²

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!