The coordinates of the vertices of angle pqr are p(-3,3), q(2,3), and r(-3,-4). find the side lengths to the nearest hundredth and the angle measures to the nearest degree.

PQ=5, QR=radical 61= 7.81, angle: 50degrees,Why:PQ=|-3|+2=5PR=6angle Alfa, so there is right angle triangle PQR so I can use following formula:PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61also I can use: sinus (angle)=PR/QR;sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=0,7660}.