![\bf 2x+\sqrt{4x^2}+\sqrt[3]{8x^3}\qquad \begin{cases} 4\to 2^2\\ 8\to 2^3 \end{cases}\qquad thus \\\\\\ 2x+\sqrt{2^2x^2}+\sqrt[3]{2^3x^3}\implies 2x+\sqrt{(2x)^2}+\sqrt[3]{(2x)^3} \\\\\\ 2x+2x+2x=\boxed{6x}](/tpl/images/0275/7130/03363.png)
Igot it wrong and have no clue how to get to the right answer!
...
Answers: 2
Another question on Mathematics
Mathematics, 21.06.2019 19:40
Which of the binomials below is a factor of this exression? 16x^2+40xy+25y^2 a.4x-5y b. 2x-5y c.4x+5y d.2x+5y
Answers: 2
Mathematics, 21.06.2019 21:50
Solve the following pair of equations for x and y: ax/b_ by /a= a +b; ax - by = 2ab
Answers: 2
You know the right answer?
Questions
History, 30.01.2020 14:01
Biology, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
Social Studies, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
History, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
Mathematics, 30.01.2020 14:01
