Sam ran 63,756 feet in 70 minutes. what is sam's rate in miles per hour? ( there are 5,280 feet in one mile.)

Sam's rate will be 10.347 miles per hour

Firstly, we'll convert 63,756 feet to miles and this will be:

= 63756/5280

= 12.075 miles

Then, we'll convert 70 minutes to hours and this will be:

= 70/60

= 1.167 hours

Therefore, Sam's rate in miles per hour will be:

= 12.075 miles/1.167 hours

= 10.347 miles per hour.

In conclusion, Sam's rate is 10.347 miles per hour.

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Sam's rate in miles per hour was 10.35 mph.

Given that Sam ran 63,756 feet in 70 minutes, to determine what is Sam's rate in miles per hour, knowing that there are 5,280 feet in one mile, the following cross multiplication calculation must be performed:

Therefore, Sam's rate in miles per hour was 10.35 mph.

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the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

2,160 π

step-by-step explanation: