Find the zeroes of 6x^4+x^3+2x^2-4x+1

By the rational root theorem, you have the following candidates for roots:



Plugging in each of these will tell you which one is actually a zero. You'll find that both and both work, which means and are linear factors to the quartic.

To find the remaining factor(s), divide the quartic by the known factors:




Since has no real roots, you are left with



which has two real zeros at , . It also has two complex roots at .

Answer for 2: his profit would be $2.88 explanation: you have to first multiply 72 and 0.12 together to get $8.64 once you do that you know how much money the shopkeeper made from selling the candy bars individually. so you have to do 8.64-5.76=2.88 hope that ; )answer for 3: yeah i’m sorry i have no idea what number 3 is. i’m sorry i couldn’t with that.

put like terms together.orremember that the 45 becomes negative when moved to the other side.orthe minuses cancel out.