Scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points. what is the minimum score you would need to be in the top 5%?

Using the normal distribution, it is found that the minimum score to be in the top 5% is of 86.4.

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In a normal distribution, the z-score is used.

In this problem:

The minimum score needed to be in the top 5% is of 86.4.

A similar problem is given at link

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high