Y= x +2 and y=3x-4 solved using substitution

So I did this:

y=x +2
y=3x-4

I used the first equation to plug into the second equation.
x+2= 3x -4
I subtracted 3 from both sides so I get
-2x+2=-4
So I subtract 2 from both sides so I get
-2x=-6
I divide -2 on both sides and so I get
x=3
Then I plug the x into either equation. I did the first equation.
y=3+2
y=5
So x=3 and y=5

D. i think it is the savings

The answer to your question is b’(16,14)