Two polygons are similar. the perimeter of the smaller polygon is 48 centimeters and the ratio of the corresponding side lengths is 2/3. find the perimeter of the other polygon.

the perimeter of the other polygon is .

The scale factor is 1.3 repeating all you have to do is divide the side of the larger tirangle by the smaller corresponding sides, example 6 divided by 4.5 
A is congruent to L
C is congruent to N
B is congruent to M 
ABC is congruent to LMN
hope this helped you again

Answer: 10pi

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

now i kniw my abcs next time wont u sing with me