Ahollow ball is made of rubber that is 1 cm thick. the ball has a radius of 5 cm at the outside surface. what is the approximate volume of rubber used to make the ball? use 3.14 to approximate pi.
255.4 cm³
267.9 cm³
523.3 cm³
2043.1 cm³

Option 1. 255.4 cm³

Step-by-step explanation:

Since radius of the ball at the outer surface is = 5 cm³

Therefore volume of the ball formed by outer surface = (4/3)×π×5³ cm³

The ball is made up of 1 cm thick rubber so the radius of ball with inner surface = 5-1 = 4 cm

and volume of the ball formed by inner surface = (4/3)×π×4³ cm³

Now the volume of the rubber = Volume of the ball with outer layer - Volume of the ball with inner layer

V = (4/3)×π×5³ - (4/3)×π×4³ = (4/3)×π×(5³- 4³) = (4/3)×3.14×(61) = 255.38

V = 255.4 cm³

Option 1. 255.4 cm³ is the correct answer.

b

step-by-step explanation:

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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