Aspinner contains four sections: red, blue, green, and yellow. joaquin spins the spinner twice. the set of outcomes is given as s = {rb, rg, ry, rr, br, bg, by, bb, gr, gb, gy, gg, yr, yb, yg, yy}. if the random variable is “yellow (y),” which of the following is the correct probability distribution?

Step-by-step explanation:

Given that  spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as

S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}.

If the random variable is “yellow (Y),” let us first find the values that Y can take.

From the sample space given above, we find that Y can take only 3 values 0,1,2

In the sample space of 16 entries, Y occurs 0 times in 9 times

1 time in 6 times and 2 times 1 time

Hence probability = no of favouable outcomes/number in sample space

So

P(Y=0) = 9/16

P(Y=1) = 6/16 = 3/8

P(Y=2) = 1/16

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.