André solves the following system of equations by elimination.
3a+6b=12
-3a+6b=-12
what is the resulting equation?
12b = 0
6a = 0
–6a = 0
–12b = –24

12b = 0

Step-by-step explanation:

We are given that,

André solves the following system using elimination method.

3a+6b=12

-3a+6b=-12

Now, in elimination method, we eliminate any one variable from the equations to obtain an equation in single variable.

As, from the system, we see that,

The variable 'a' can be removed by adding both the equations.

So, after adding the equations, we have,

(3a+6b) + (-3a+6b) = 12 + (-12)

i.e. (3a-3a) + (6b+6b) = 12 - 12

i.e. 12b = 0

Hence, the resulting equation is '12b=0'.

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step-by-step explanation:

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