If u = {all positive integers} and a = {x|x ∈ u and x is an odd positive integer}, which describes ac?
ac = {x|x ∈ u and is a negative integer}
ac = {x|x ∈ u and is zero}
ac = {x|x ∈ u and is not an integer}
ac = {x|x ∈ u and is an even positive integer}

Given:

Universal set is all positive integers {1,2,3...}

Set A is the set of all positive ODD integers {1,3,5,7...}

The question asks us to find , which is the complement of set A. The complement of a set refers to elements NOT in that set. Hence, complement of A should be all the elements NOT in A but in Universal Set, U.

It is clear from the question that set A houses all the odd positive numbers, so complement of A will have all the even positive numbers. Last choice is the correct one.

ANSWER: "{x|x ∈ U and is an even positive integer}"

Step-by-step explanation:

Given: If which represents the Universal set of all positive integers and which represents the set of odd positive integers .

We know that the complement of any set X is given by :-

Then the complement of set A is given by :-

[ Since when we subtract all the odd positive numbers from the set of positive numbers then all the even numbers will left. ]

yep

step-by-step explanation: