Ateacher surveyed her class after they had taken a vocabulary test. eighteen of the students claimed they had studied at least one hour for the test. the remaining twelve students admitted that they had not studied for the test at all. the test results (expressed as a percent) for the two groups are shown below.
studied: 88, 100, 94, 79, 92, 100, 95, 83, 89, 99, 100, 91, 89, 95, 100, 93, 96, 84
did not study: 82, 72, 45, 91, 58, 83, 65, 87, 90, 77, 73, 89
1. calculate the range and interquartile range for each set of data.
2. using complete sentences, compare the data sets based on your results in part a.

1.   studied:   range = 21, iqr = 10; did not study:   range = 46, iqr = 19.5

2.   the set of data for students that did not study had more variation than that of the students that did study; this means the students that studied had more consistent test scores.

step-by-step explanation:

first we will order each set from least to greatest:

studied - 79, 83, 84, 88, 89, 89, 92, 92, 93, 94, 95, 95, 96, 99, 100, 100, 100, 100

did not study - 45, 58, 65, 72, 73, 77, 82, 83, 87, 89, 90, 91

to find the range, we subtract the highest and lowest values for each set.

studied = 100-79 = 21

did not study = 91-45 = 46

to find the interquartile range (iqr), we first find the median, q1 and q3:

studied:   median = 93.5; q1 = 89; q3 = 99

did not study:   median = 79.5; q1 = 68.5; q3 = 88

to find the iqr subtract q3 and q1:

studied = 99-89 = 10

did not study = 88-68.5 = 19.5

since the did not study group had a larger interquartile range and range, it had greater variation.   this means the other group, studied, was more consistent.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

sine

step-by-step explanation: