Mathematics, 18.08.2019 22:30 mlandon922

Two fifths of the instruments in the marching band are brass, one third are percussion, and the rest are woodwinds. a. what fraction of the band are wood winds b. one half of the woodwinds are clarinets. what fraction of the band is clarinets c. one eighth of the brass instruments are tuba. if there are 240 instruments in the band, how many are tubas. to the users answer one if you must i will give you a point as we'll

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A. What fraction of the band are woodwinds?
First, find common denominators for the first two. Let's use 15.
6/15 is brass (5x3=15, and 2x3=6)
5/15 is percussion (3x5=15, and 1x5=5)
Now, we add the two and subtract them from the whole.
6/15 + 5/15 = 11/15
15/15 - 11/15 = 4/15
4/15 of the band is woodwinds.

B. One half of the woodwinds are clarinets. What fraction of the band is clarinets?
To find this, we take our 4/15 and divide it by two. Thankfully, the numerator is an even number, so it splits in half easily.
4/15 divided by 2 = 2/15
2/15 of the band is clarinets.

C. One eighth of the brass instruments are tubas. If there are 240 instruments in the band, how many are tubas?
First, find 1/8 of the number of brass instruments.
6/15 of the band is brass.
We need to make this an equivalent fraction that is divisible by 8.
Both 6 and 8 go into 24, so we'll multiply our fraction by 4, since 6x4=24
The new fraction is
24/60
Now, we divide that fraction by 8, to find 1/8 of the brass instruments.
24/8=3
3/60 of the band is tubas.
To find the number of tubas out of a 240 instrument band, we multiply the fraction of tubas by the whole band.
3/60 x 240 = 12
There are 12 tubas in the band.

Answer from: Quest

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that $\frac{ab}{de}=\frac{bc}{ef}$ .

also, it is given that $\frac{ab}{de}=\frac{3}{4}$

so, from the options, we need that $\frac{bc}{ef}=\frac{3}{4}$ .

a. $\frac{bc}{ef}=\frac{6}{9}=\frac{2}{3}$

b. $\frac{bc}{ef}=\frac{4}{6}=\frac{2}{3}$

c. $\frac{bc}{ef}=\frac{8}{12}=\frac{2}{3}$

d. $\frac{bc}{ef}=\frac{12}{16}=\frac{3}{4}$

as, we can see that only option d gives the same ratio as $\frac{ab}{de}=\frac{3}{4}$ i.e. $\frac{bc}{ef}=\frac{3}{4}$ .

hence, the possible lengths are bc = 12 and ef = 16.

Answer from: Quest

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be). so point b is at (-2,2). point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

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