Identify the outlier in the data. then find the mean when the outlier is included and when it is not included.
68, 63, 67, 66, 65, 87, 69, 61, 86, 82, 28

a. outlier is 28; mean with outlier = 67; mean without outlier = 67.5

b. outlier is 28; mean with outlier = 74.2; mean without outlier = 71.4

c. outlier is 28; mean with outlier = 67.5; mean without outlier = 71.4

d. outlier is 28; mean with outlier = 67.5; mean without outlier = 64.9

can i get the link to the assignment?

step-by-step explanation:

the answer is 21%.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.