Prove that the angle bisectors of a rhombus are concurrent. then prove that the point where the angle bisectors intersect is equidistant from all sides of the rhombus.

All of the given choices are quadrilaterals. They only differ on the number of their parallel sides. A square has 2 parallel sides and all of its sides are equal or the same. A rhombus has 2 parallel sides and all of its sides are equal or only two of its sides are equal.