Ihave no idea how to use this site yet, so i'm just gonna put my algebra problem here. for any !
graph system of equation:
x-2y=2
3+y=6

I have a hard times putting graphs so I'll just put the answers and say how to graph with paper
so we notice that if we solve the second equation (3+y=6), we get a value for y and no value for x so just draw a horizonal line at the point 3 on the y axis

then make the second equation into slope inercept form y=mx+b
x-2y=2
2y-x=-2
2y=x+2
y=1/2x+1
just put in values for x and get y values, then plot points and get line
find where the line inercepts/crosses the first line (3+y=6) and that is the solution

OR

so a the solution is when both equations are true so just assume both are true and solve for x and y

x-2y=2
3+y=6

first of all the second equation is easy
3+y=6
subtract 3 from both sides
y=3

so we subsitute 3 for y in first equation
x-2(3)=2
x-6=2
add 6 to both sides
x=8
y=3
the solution is the point (8,3)

1.3 and 1 1/3 are both closest to 1. hope this ; )

And i oop, gurlll he not gonna have no more left .. anna ou