Use gauss-jordan elimination to solve the following linear system.
x – 6y – 3z = 4
–2x – 3z = –8
–2x + 2y – 3z = –14

a. (–3,–2,4)
b. (–2,–3,4)
c. (5,3,–5)
d. (–5,–3,3)

Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14


mulstiply 2nd row by -1 and add to 3rd

divde last row by 2

multiply 2rd row by 6 and add to top one

multiply 1st row by -1 and add to 2nd

divide 2nd row by -3

mulstiply 2nd row by -1 and add to 1st row

divide 1st row by -3


rerange


x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer