There is a margin error in a survey of +/– 4%. what is the range of the number of students who wish they could wear shorts if 111 of 210 students wished they could wear shorts to school and there are 903 students at the school?

Hi, thank you for posting your question here at .

First, we find the center of the range through ratio and proportion:

111/210 = x/903
x = 477

Since there is a 4% margin error,

477(0.04) = 19, we subtract and add 19 to 477 to determine the lower and the upper limit of the range, respectively.

477 - 19 = 458 
477 + 19=496

Therefore, the range is 458 to 496.

I'm not sure but i think it's 1670km/h