Need with math asap identify the following for the function: f(x)=log(x/8) x-intercept: y-intercept: domain: range: the other two questions are in pics down below. explain these questions i'm really confused. you

Eight answers for six points, eh ?
You're a tough businessman.

F(x)=log(x/8)

X-intercept . . . the point where the function crosses the x-axis (f(x) is zero).

                                     log(x/8) = zero

                               10^log(x/8)  =  10^0
                                           \/          \/
                                         (x/8)  =    1

                                            x  =  8

y-intercept . . . the point where the function crosses the y-axis, ('x' is zero).

                                      Y  =   log(0/8)

                                         =    log( 0 )

                                         =  negative infinity.

Domain (everything that 'x' can be) . . . all positive numbers.

Range  (everything that f(x) can be) . . . - inf  to  + inf .


First picture:      f(x) = -3 / x⁴

To get an idea of what the asymptotes are, you have to draw
the graph of the function, either on paper or in your mind.
Think of what the function does, as 'x' drifts in from very
far away on the left, crosses over zero, and drifts far away
to the right.

'x' is very far away, negative . . .  f(x) is positive, very small

'x' is negative 1 . . . . .  f(x) = 3

'x' is close to zero, on the negative side . . . f(x) is positive, gigantic

'x' is close to zero, on the positive side . . .  f(x) is negative, gigantic

'x' is very far away, positive . . .  f(x) is negative, very small .

The horizontal asymptote is the x-axis.
The vertical asymptote is the y-axis.


Second picture:      f(x)= 1/x  ===>  g(x)= -1/x + 3

Two transformations:

                   -- f(x) ==>  -f(x)  (reflect it across the x-axis)

                   --  -f(x) ==>  -f(x)+3  (translate it UP by 3 units)

The answer to your question is the last one