If the sin 60 degrees is the square root of 3 over 2 then the =

If Sin 60 = √3 / 2

Then, Cos 60 = ?

Well, we know :

Sin^2x + Cos^2x = 1

Let X = 60°

That is,

Sin^2(60) + Cos^2(60) = 1

(√3 / 2)^2 + Cos^2(60) = 1

3 / 4 + Cos^2(60) = 1

Cos^2(60) = 1 - 3/4

Cos^2(60) = 4/4 - 3/4

Cos^2(60) = (4-3)/4

Cos^2(60) = 1/4

Cos(60) = √(1/4)

Cos(60) = √1 / √4

Cos(60) = 1 / 2

This's answer right to the your question.

The correct answer is .44