Given that y=14/√(1+6x^3 ), find dy/dx and use it to find an approximate change in y when x changes from 2 to 2.003. hence, find an approximate value of y when x= 2.003

C. i believe it is (5×(-20))+(100×(0.7))

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm