You want to draw an enlargement of a design that is printed on a card that is 4in by 5in. you will be drawing this design on an piece of paper that is 8 1/2in by 11in. what are the dimensions of the largest complete enlargement you can make?

8.5 inch × 10.625 inch.

Step-by-step explanation:

We have the dimensions of the card are 4 inch × 5 inch.

Also, the dimensions of the paper are i.e. 8.5 inch × 11 inch.

Now, the possible enlargement in the sides are given by,

So, the maximum enlargement possible is 2.125x, where x represents the values of the dimensions of the cards.

Thus, the maximum enlargement possible is 2.125 × 4 = 8.5 and 2.125 × 5 =10.625.

Hence, the dimensions of the largest enlargement possible are 8.5 inch × 10.625 inch.

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length