Which polynomial is factored completely?

121x^2+36y^2

(4x+4)(x+1)

2x(x^2-4)

3x^4-15n^3+12n^2

Complete factored: (4x+4)(x+1) and 2x(x²-4)

Step-by-step explanation:

We have to check each option one by one

Option 1:

It is sum of two perfect square, As we know sum of two perfect square can't be factored. It is prime equation.

False

Option 2:

Here we have two factor (4x+4) and (x+1). In both factor degree of x is 1. It is complete factor form.

Complete factor:

True

Option 3:

Here we have two factor 4x and x²-4. For second factor it is further factor. Because it is difference of square. Factor of x²-4 = (x+2)(x-2)

Complete Factor: 2x(x+2)(x-2)[/tex]

True

Option 4:

Here variable are not same. So, it can't be factor.

False

The completely factored polynomials are and . Option (b) and option (c) are correct.

Further Explanation:

Given:

The options are as follows,

(a).

(b).

(c).

(d).

Calculation:

In option (a)

The expression is not in the factored form. option (a) is not correct.

In option (b)

The expression is in the factored form.

Option (b) is correct.

In option (c)

The expression is in the factored form.

Option (c) is correct.

In option (d)

The expression is not in the factored form.

Option (d) is not correct.

The completely factored polynomials are and Option (b) and option (c) are correct.

Learn more:

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: solution, factored, completely, polynomial, factorized form, expression, difference of cubes, exponents, power, equation, power rule, exponent rule.

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step-by-step explanation:

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step-by-step explanation: