Asquare painting is surrounded by a frame. the outside edges of the frame are x inches in length and there is a 4-inch border between the painting and the frame. what is the total area of the border?

16x-64 square inches

Step-by-step explanation:

Given that a square painting is surrounded by a frame. The outside edges of the frame are x inches in length and there is a 4-inch border between the painting and the frame.

Thus the square frame consists of an outer square with side x inches and inner square with side x-4(2)

The area of the border

=

area of outer square-area of inner square

=x^2-(x-8)^2

= (2x-8)(8)

=16x-64

the answer is a

step-by-step explanation:

because your just changing the position of where the shape is

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy