Solve x2 14x = −24 by completing the square. what is the solution set of the equation?
a. {−12, −2}
b. {−7, 7}
c. {−6, −4}
d. {−5, 5}

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x +24 = 0

Let the coefficients be:

a = 1
b = 14
c = 24

To complete the square, add (b/2)^2 to both sides of the equation:

(b/2)^2 = 49

x^2 + 14x + 49 + 24 = 49
x^2 + 14x + 49 = 25
(x+7)^2 = 25

Therefore, the solution set of the equation is {-12, -2}