Factor completely. x 3 + 6x 2 - 4x - 24
a.(x + 6)(x - 2)(x + 2)
b.(x + 2)(x - 6)(x + 2...
Mathematics, 02.10.2019 01:30 shay7298
Factor completely. x 3 + 6x 2 - 4x - 24
a.(x + 6)(x - 2)(x + 2)
b.(x + 2)(x - 6)(x + 2)
c.(x - 6)(x + 2)(x + 2)x^3 + 6x^2 - 4x - 24 = x^2(x + 6) - 4(x + 6) = (x + 6)(x^2 - 4) = (x + 6)(x + 2)(x - 2)
Answers: 2
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