Suppose you're given the formula r = s + 2t. if you know that s is three times greater than t, how could you rewrite the formula?
a. r = 3(s + t)
b. r = 5t
c. r = 3(s + 2t)
d. r = 5s

B .    R = 5t

Step-by-step explanation:

From the question above; given that R = S + 2t

If s is three times greater than t, it simply means s = 3t

so, we can easily substitute s= 3t in the initial equation.

Replacing or substituting s = 3t in the  equation: R = S + 2t, the equation becomes;

R =  3t  +  2t

R = 5t

Therefore we could re-write the formula as R = 5t

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)