If f(x)=2x^2-5 and g(x)=3x+3 find (f-g)(x)

(f-g)(x) = 2x^2 - 5 - (3x+3)

(f-g)(x) = 2x^2 - 5 - 3x - 3

(f-g)(x) = 2x^2 - 3x -8

(f-g)(x)= 2x^2-3x - 8

Step-by-step explanation:

If f(x)=2x^2-5 and g(x)=3x+3 find (f-g)(x)

(f-g)(x)= f(x) - g(x)

LEts subtract f(x)- g(x). plug in given f(x) and g(x)

Replace f(x) with 2x^2 -5  and g(x) with 3x+3

(f-g)(x)= f(x) - g(x) = (2x^2 -5) - (3x+3)

We have negative sign in between , distribute negative inside the second parenthesis

(f-g)(x)= 2x^2 -5 -3x - 3

Now combine like terms

(f-g)(x)= 2x^2-3x - 8

i cant see the graph

step-by-step explanation: