An automobile purchased for 17000 is worth 2600 after 6 years assuming that the car's value depreciated steadily from year to year what was it worth at the end of the third year

subtracting $2,600 from $29,000 gives you the amount of value the car has lost in total  divide by 6 to figure out how much value the car loses per year (26,400/6 = $4,400). Now you know that the car loses $4,400 in value each year. go back and subtract three times $4,400 from the original price of the car to find it's value after the third year (29,000 - (3x4,400) = 15,800). Thus, after three years, the value of the car will be -> $15,800.

$17,000 - $2600 = $14,400
$14,400 ÷ 6 = $2,400 (this is the number to deduct each year)
So $17,000 - $2,400 = $14,600 first year
$14,600 - $2,400 = $12,200 second year
$12,200 - $2,400 = $9,800 third year
Your answer is $9,800

If you keep going to confirm your work the 6th year will be $2,600

Okay so for every triangle has three angles that always add up to 180 degrees. and to tell the difference between whether they are secure, right or obtuse is that acute: has one angle that is less than 90 degrees. right triangle means there is at least one angle that is exactly 90 degrees. and an obtuse angle has an angle that is bigger than 180 degrees. i’ll do #13 as an example: 13. 40 and 50 so if every triangle has 180 degrees 40+50= 90 degrees then180-90= 90 degrees so the third angle is 90 degrees and because this triangle has a 90 degree angle it means it is a right triangle