Graph the functions below. arrange the parabolas with respect to the position of their vertices from left to right.
y=f(4x+3)
y=f(x-3)
y=f(2x-1)
y=f(x/2-2
y=f(x-7)
y=f(x+3) /3
y=f(x-2)

6  1  3  7  2  4  5

Step-by-step explanation:

Let us initially consider that the vertex of F(x) is (0,0).

1: now for y=F(4x+3)

the vertex is .

2: for y=F(x-3)

the vertex is 3.

3: for y=F(2x-1)

the vertex is .

4: for y=F(x/2-2)

the vertex is 4.

5: for y=F(x-7)

the vertex is 7.

6: for y=F(x+3)/3

the vertex is -3.

7: for y=F(x-2)

the vertex is 2.

Hence on arranging based on the vertex from left to right we get that it is arranged as:

6  1  3  7  2  4  5

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4