Which equation could have been used to create this function table?
x | y
1 3
2 6
4 12
5 15
6 18
a. y = x + 3
b. y = x + 2
c. y = 4x
d. y = 3x

(1,3)(2,6)
slope = (6 - 3) / (2 - 1) = 3/1 = 3

y = mx + b
slope(m) = 3
use any of ur points(1,3)...x = 1 and y = 3
now we sub and find b, the y int
3 = 3(1) + b
3 = 3 + b
3 - 3 = b
0 = b

so ur equation is : y = 3x + 0...or just y = 3x

1/5 i hope this