Aplane at 3,800 feet is descending at a rate of 120 feet per minute, and a plane at 520 feet is climbing at a rate of 40 feet per minute. in how many minutes will they be at the same altitude? write a system of equations. then graph the system to determine the solution.

so the basic formula for this d = rt

where d is the distance , r is the speed and t is time

3800 – 120t = 520 + 40t ( this is the altitude of each plane are equal)

Solve for t

T = 20.5 min time it takes for the planes to be at the same altitude

3800 – 120(20.5) = 1340 ft

how long did the flood last

step-by-step explanation:

then i will answer

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine